2(sec^2x+cos^2x)=5

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Solution for 2(sec^2x+cos^2x)=5 equation: 


Simplifying
2(sec2x + cos2x) = 5

Reorder the terms:
2(cos2x + c2esx) = 5
(cos2x * 2 + c2esx * 2) = 5
(2cos2x + 2c2esx) = 5

Solving
2cos2x + 2c2esx = 5

Solving for variable 'c'.

Reorder the terms:
-5 + 2cos2x + 2c2esx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 2cos2x + 2c2esx = 0

The solution to this equation could not be determined.

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